2020-03-14 polyhedral homotopy epsilon local rigidity.jl
using HomotopyContinuation, LinearAlgebra
#=
Here we change coordinates to the moving frame
=#
function set_locations(p0)
# p0 should be an n by d array, p0[1,:] gives the coords of node 1
# returns a new configuration \widehat{p0}
# which has been translated and rotated
# ASSUME nodes 1,2,3 CONNECTED and NON-COLLINEAR
# here we change coordinates so that
# node 1 has coordinates 0,0,0
# node 2 has coordinates *,0,0
# node 3 has coordinates *,*,0
p1 = translate_coordinates(p0)
p2 = rotate_coordinates(p1)
return p2
end
function rotate_coordinates(p0)
# p0 should be an n by d array, p0[1,:] gives the coords of node 1
# ASSUME node 1 has coordinates 0,0,0 (already TRANSLATED)
# ASSUME nodes 1,2,3 CONNECTED and NON-COLLINEAR
# here we change coordinates so that
# node 1 has coordinates 0,0,0
# node 2 has coordinates *,0,0
# node 3 has coordinates *,*,0
n,d = size(p0)
if d==3
v2 = p0[2,:] #p0[2]
v3 = p0[3,:] #p0[3]
V = hcat(v2,v3)
Q,R = qr(V)
p1 = p0*Q # equivalently applies Q' to every column vector p0[i,:]
elseif d==2
Q,R = qr(p0[2,:])
p1 = p0*Q # equivalently applies Q' to every column vector p0[i,:]
end
return p1
end
function translate_coordinates(p0)
# p0 should be an n by d array, p0[1,:] gives the coords of node 1
# ASSUME nodes 1,2,3 CONNECTED and NON-COLLINEAR
# here we change coordinates so that
# node 1 has coordinates 0,0,0
n,d = size(p0)
p1 = zeros(n,d)
for i in 2:n
p1[i,:] = p0[i,:] - p0[1,:]
end
return p1
end
function get_equation(p0, x, edge)
i,j = edge
v = x[j,:] - x[i,:]
w = p0[j,:] - p0[i,:]
gij = sum([vi^2 for vi in v]) - sum(wi^2 for wi in w)
return gij
end
#=
Here is the "epsilon local rigidity" test.
This code was needing 67 million paths for total degree homotopy.
=#
ht = 3
p0 = [1 0 0; -1/2 sqrt(3)/2 0; -1/2 -sqrt(3)/2 0;
-sqrt(3)/2 -1/2 ht; sqrt(3)/2 -1/2 ht; 0 1 ht]
edges = [(1,2),(1,3),(1,4),(1,5),(2,3),(2,5),
(2,6),(3,4),(3,6),(4,5),(4,6),(5,6)]
m = length(edges)
n,d = size(p0)
N = n*d - binomial(d+1,2)
@polyvar x[1:n,1:d]
p0 = set_locations(p0)
g = [get_equation(p0,x,edge) for edge in edges]
subz = Dict(x[i,k] => 0 for i in 1:n for k in 1:d if k >= i)
g = [subs(gij, subz...) for gij in g]
# "g" contains the squared edge length equations
# the ε-sphere equation
ε = 0.1 # you could change this
s = sum([ (x[i,k]-p0[i,k])^2 for i in 1:n for k in 1:d ]) - ε^2
s = subs(s, subz...)
# our one polynomial
G = sum([gi^2 for gi in g]) + s^2
# add Gaussian noise
y0 = p0 + randn(Float64,n,d)
# only the lower number of variables
Nvarz = [x[i,k] for i in 1:n for k in 1:d if k < i]
∇G = differentiate(G, Nvarz)
xminusy = [x[i,k] - y0[i,k] for i in 1:n for k in 1:d if k < i]
# affine chart of projective space
@polyvar λ[1:2]
a = rand(Float64, 2,1) # random affine chart of projective space
lagrange = λ[1]*∇G + λ[2]*xminusy
chart = sum(λ.*a) - 1
# "G" is one polynomial, the sum of squares of all the
# squared edge length equations, one for each edge,
# and the sphere equation too.
# "lagrange" and "chart" are the equations for Euclidean distance minimization
F = vcat(G,lagrange,chart)
display(bezout_number(F))
# multi-homogeneous Bezout number is only 8 million or so
vars = variables(F)
display(bezout_number(F; variable_groups=[vars[1:12],vars[13:14]]))
# even better is the mixed volume, which gives about 1 million paths!
display(mixed_volume(F))
# random seed was 525849.
resultpolyhedral = solve(F; start_system = :polyhedral)
# zero real solutions.
rs = real_solutions(resultpolyhedral)
display(resultpolyhedral)