Revision 41d54d3bf83f62d3ff5948cb788fe6007e66a0d0 authored by Christoph Lameter on 03 July 2008, 14:14:26 UTC, committed by Pekka Enberg on 03 July 2008, 16:01:55 UTC
The 192 byte cache is not necessary if we have a basic alignment of 128
byte. If it would be used then the 192 would be aligned to the next 128 byte
boundary which would result in another 256 byte cache. Two 256 kmalloc caches
cause sysfs to complain about a duplicate entry.

MIPS needs 128 byte aligned kmalloc caches and spits out warnings on boot without
this patch.

Signed-off-by: Christoph Lameter <cl@linux-foundation.org>
Signed-off-by: Pekka Enberg <penberg@cs.helsinki.fi>
1 parent 481c534
Raw File
cpu-load.txt
CPU load
--------

Linux exports various bits of information via `/proc/stat' and
`/proc/uptime' that userland tools, such as top(1), use to calculate
the average time system spent in a particular state, for example:

    $ iostat
    Linux 2.6.18.3-exp (linmac)     02/20/2007

    avg-cpu:  %user   %nice %system %iowait  %steal   %idle
              10.01    0.00    2.92    5.44    0.00   81.63

    ...

Here the system thinks that over the default sampling period the
system spent 10.01% of the time doing work in user space, 2.92% in the
kernel, and was overall 81.63% of the time idle.

In most cases the `/proc/stat' information reflects the reality quite
closely, however due to the nature of how/when the kernel collects
this data sometimes it can not be trusted at all.

So how is this information collected?  Whenever timer interrupt is
signalled the kernel looks what kind of task was running at this
moment and increments the counter that corresponds to this tasks
kind/state.  The problem with this is that the system could have
switched between various states multiple times between two timer
interrupts yet the counter is incremented only for the last state.


Example
-------

If we imagine the system with one task that periodically burns cycles
in the following manner:

 time line between two timer interrupts
|--------------------------------------|
 ^                                    ^
 |_ something begins working          |
                                      |_ something goes to sleep
                                     (only to be awaken quite soon)

In the above situation the system will be 0% loaded according to the
`/proc/stat' (since the timer interrupt will always happen when the
system is executing the idle handler), but in reality the load is
closer to 99%.

One can imagine many more situations where this behavior of the kernel
will lead to quite erratic information inside `/proc/stat'.


/* gcc -o hog smallhog.c */
#include <time.h>
#include <limits.h>
#include <signal.h>
#include <sys/time.h>
#define HIST 10

static volatile sig_atomic_t stop;

static void sighandler (int signr)
{
     (void) signr;
     stop = 1;
}
static unsigned long hog (unsigned long niters)
{
     stop = 0;
     while (!stop && --niters);
     return niters;
}
int main (void)
{
     int i;
     struct itimerval it = { .it_interval = { .tv_sec = 0, .tv_usec = 1 },
                             .it_value = { .tv_sec = 0, .tv_usec = 1 } };
     sigset_t set;
     unsigned long v[HIST];
     double tmp = 0.0;
     unsigned long n;
     signal (SIGALRM, &sighandler);
     setitimer (ITIMER_REAL, &it, NULL);

     hog (ULONG_MAX);
     for (i = 0; i < HIST; ++i) v[i] = ULONG_MAX - hog (ULONG_MAX);
     for (i = 0; i < HIST; ++i) tmp += v[i];
     tmp /= HIST;
     n = tmp - (tmp / 3.0);

     sigemptyset (&set);
     sigaddset (&set, SIGALRM);

     for (;;) {
         hog (n);
         sigwait (&set, &i);
     }
     return 0;
}


References
----------

http://lkml.org/lkml/2007/2/12/6
Documentation/filesystems/proc.txt (1.8)


Thanks
------

Con Kolivas, Pavel Machek
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