Revision adae52b94e18afa1f84fab67df2a8a872c2f5533 authored by Miao Xie on 31 March 2011, 09:43:23 UTC, committed by Chris Mason on 05 April 2011, 05:19:43 UTC
the object id of the space cache inode's key is allocated from the relative
root, just like the regular file. So we can't identify space cache inode by
checking the object id of the inode's key, and we have to clear __GFP_FS flag
at the time we look up the space cache inode.

Signed-off-by: Miao Xie <miaox@cn.fujitsu.com>
Signed-off-by: Liu Bo <liubo2009@cn.fujitsu.com>
Signed-off-by: Chris Mason <chris.mason@oracle.com>
1 parent 6e8df2a
Raw File
prio_heap.c
/*
 * Simple insertion-only static-sized priority heap containing
 * pointers, based on CLR, chapter 7
 */

#include <linux/slab.h>
#include <linux/prio_heap.h>

int heap_init(struct ptr_heap *heap, size_t size, gfp_t gfp_mask,
	      int (*gt)(void *, void *))
{
	heap->ptrs = kmalloc(size, gfp_mask);
	if (!heap->ptrs)
		return -ENOMEM;
	heap->size = 0;
	heap->max = size / sizeof(void *);
	heap->gt = gt;
	return 0;
}

void heap_free(struct ptr_heap *heap)
{
	kfree(heap->ptrs);
}

void *heap_insert(struct ptr_heap *heap, void *p)
{
	void *res;
	void **ptrs = heap->ptrs;
	int pos;

	if (heap->size < heap->max) {
		/* Heap insertion */
		pos = heap->size++;
		while (pos > 0 && heap->gt(p, ptrs[(pos-1)/2])) {
			ptrs[pos] = ptrs[(pos-1)/2];
			pos = (pos-1)/2;
		}
		ptrs[pos] = p;
		return NULL;
	}

	/* The heap is full, so something will have to be dropped */

	/* If the new pointer is greater than the current max, drop it */
	if (heap->gt(p, ptrs[0]))
		return p;

	/* Replace the current max and heapify */
	res = ptrs[0];
	ptrs[0] = p;
	pos = 0;

	while (1) {
		int left = 2 * pos + 1;
		int right = 2 * pos + 2;
		int largest = pos;
		if (left < heap->size && heap->gt(ptrs[left], p))
			largest = left;
		if (right < heap->size && heap->gt(ptrs[right], ptrs[largest]))
			largest = right;
		if (largest == pos)
			break;
		/* Push p down the heap one level and bump one up */
		ptrs[pos] = ptrs[largest];
		ptrs[largest] = p;
		pos = largest;
	}
	return res;
}
back to top