Revision e6da7c9fed111ba1243297ee6eda8e24ae11c384 authored by Eric Sandeen on 23 May 2009, 19:30:12 UTC, committed by Felix Blyakher on 02 June 2009, 03:59:38 UTC
In the case where growing a filesystem would leave the last AG
too small, the fixup code has an overflow in the calculation
of the new size with one fewer ag, because "nagcount" is a 32
bit number.  If the new filesystem has > 2^32 blocks in it
this causes a problem resulting in an EINVAL return from growfs:

 # xfs_io -f -c "truncate 19998630180864" fsfile
 # mkfs.xfs -f -bsize=4096 -dagsize=76288719b,size=3905982455b fsfile
 # mount -o loop fsfile /mnt
 # xfs_growfs /mnt

meta-data=/dev/loop0             isize=256    agcount=52,
agsize=76288719 blks
         =                       sectsz=512   attr=2
data     =                       bsize=4096   blocks=3905982455, imaxpct=5
         =                       sunit=0      swidth=0 blks
naming   =version 2              bsize=4096   ascii-ci=0
log      =internal               bsize=4096   blocks=32768, version=2
         =                       sectsz=512   sunit=0 blks, lazy-count=0
realtime =none                   extsz=4096   blocks=0, rtextents=0
xfs_growfs: XFS_IOC_FSGROWFSDATA xfsctl failed: Invalid argument

Reported-by: richard.ems@cape-horn-eng.com
Signed-off-by: Eric Sandeen <sandeen@sandeen.net>
Reviewed-by: Christoph Hellwig <hch@lst.de>
Reviewed-by: Felix Blyakher <felixb@sgi.com>
Signed-off-by: Felix Blyakher <felixb@sgi.com>
1 parent 1f23920
Raw File
io_ordering.txt
On some platforms, so-called memory-mapped I/O is weakly ordered.  On such
platforms, driver writers are responsible for ensuring that I/O writes to
memory-mapped addresses on their device arrive in the order intended.  This is
typically done by reading a 'safe' device or bridge register, causing the I/O
chipset to flush pending writes to the device before any reads are posted.  A
driver would usually use this technique immediately prior to the exit of a
critical section of code protected by spinlocks.  This would ensure that
subsequent writes to I/O space arrived only after all prior writes (much like a
memory barrier op, mb(), only with respect to I/O).

A more concrete example from a hypothetical device driver:

        ...
CPU A:  spin_lock_irqsave(&dev_lock, flags)
CPU A:  val = readl(my_status);
CPU A:  ...
CPU A:  writel(newval, ring_ptr);
CPU A:  spin_unlock_irqrestore(&dev_lock, flags)
        ...
CPU B:  spin_lock_irqsave(&dev_lock, flags)
CPU B:  val = readl(my_status);
CPU B:  ...
CPU B:  writel(newval2, ring_ptr);
CPU B:  spin_unlock_irqrestore(&dev_lock, flags)
        ...

In the case above, the device may receive newval2 before it receives newval,
which could cause problems.  Fixing it is easy enough though:

        ...
CPU A:  spin_lock_irqsave(&dev_lock, flags)
CPU A:  val = readl(my_status);
CPU A:  ...
CPU A:  writel(newval, ring_ptr);
CPU A:  (void)readl(safe_register); /* maybe a config register? */
CPU A:  spin_unlock_irqrestore(&dev_lock, flags)
        ...
CPU B:  spin_lock_irqsave(&dev_lock, flags)
CPU B:  val = readl(my_status);
CPU B:  ...
CPU B:  writel(newval2, ring_ptr);
CPU B:  (void)readl(safe_register); /* maybe a config register? */
CPU B:  spin_unlock_irqrestore(&dev_lock, flags)

Here, the reads from safe_register will cause the I/O chipset to flush any
pending writes before actually posting the read to the chipset, preventing
possible data corruption.
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