Revision 6542fdbd8d000fc5b18eb3f396b5d18f1ffd6521 authored by Paul Russo on 13 June 2008, 20:34:11 UTC, committed by Paul Russo on 13 June 2008, 20:34:11 UTC
"int" so that NULL translates to a constant integral type. The C++ standard has this to say in section 4.10 Pointer conversions [conv.ptr]: A "null pointer constant" is an integral constant expression (5.19) rvalue of integer type that evaluates to zero. This is a problem in a function overloading situation like this: void f(double); void f(char*); int main() { for (int i = 1; i < 10; ++i) { f(i); } } The rule in section 4.10 on null pointer constants and the rules in Chapter 13 Overloading, make f(char*) a non-viable function for overloading purposes because i is not a "integral constant expression". However given: #define POGO 0 then in the same loop a call written: f(POGO); is ambiguous since both of the functions are viable (because POGO is substituted with 0, which is an integral constant expression). In cint "#define int MyType" is implemented as a variable definition using the special type macroInt$. So we need to make that type const so that overloading works correctly. Note that this is all a gross hack to paper over the fact that cint does not have a proper preprocessor. -- Paul Russo and Philippe Canal git-svn-id: http://root.cern.ch/svn/root/trunk@24273 27541ba8-7e3a-0410-8455-c3a389f83636
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README | ||
bindings | ||
build | ||
cint | ||
config | ||
core | ||
doc | ||
etc | ||
fonts | ||
geom | ||
graf2d | ||
graf3d | ||
gui | ||
hist | ||
html | ||
icons | ||
io | ||
macros | ||
main | ||
man | ||
math | ||
misc | ||
montecarlo | ||
net | ||
proof | ||
roofit | ||
rootx | ||
sql | ||
test | ||
tmva | ||
tree | ||
tutorials | ||
LICENSE | -rw-r--r-- | 25.8 KB |
Makefile | -rw-r--r-- | 40.0 KB |
configure | -rwxr-xr-x | 177.0 KB |
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