Revision 6542fdbd8d000fc5b18eb3f396b5d18f1ffd6521 authored by Paul Russo on 13 June 2008, 20:34:11 UTC, committed by Paul Russo on 13 June 2008, 20:34:11 UTC
"int" so that NULL translates to a constant integral type. The C++ standard has this to say in section 4.10 Pointer conversions [conv.ptr]: A "null pointer constant" is an integral constant expression (5.19) rvalue of integer type that evaluates to zero. This is a problem in a function overloading situation like this: void f(double); void f(char*); int main() { for (int i = 1; i < 10; ++i) { f(i); } } The rule in section 4.10 on null pointer constants and the rules in Chapter 13 Overloading, make f(char*) a non-viable function for overloading purposes because i is not a "integral constant expression". However given: #define POGO 0 then in the same loop a call written: f(POGO); is ambiguous since both of the functions are viable (because POGO is substituted with 0, which is an integral constant expression). In cint "#define int MyType" is implemented as a variable definition using the special type macroInt$. So we need to make that type const so that overloading works correctly. Note that this is all a gross hack to paper over the fact that cint does not have a proper preprocessor. -- Paul Russo and Philippe Canal git-svn-id: http://root.cern.ch/svn/root/trunk@24273 27541ba8-7e3a-0410-8455-c3a389f83636
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vmc | ||
RadioNuclides.txt | -rw-r--r-- | 811.5 KB |
gdb-backtrace-script | -rw-r--r-- | 408 bytes |
gdb-backtrace.sh | -rwxr-xr-x | 994 bytes |
hostcert.conf | -rw-r--r-- | 1.7 KB |
pdg_table.txt | -rw-r--r-- | 379.3 KB |
valgrind-root.supp | -rw-r--r-- | 4.1 KB |
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